Word problems that lead to simple linear equations, II
This is a continuation of the discussion on the word or story problems. The first task in solving word problems is to translate them into the language of mathematics: equations. Since an equation captures only essential details of a problem, the translation is not wordforword. Inessential details must be left out.
(Note: In the applet below, all underlied words and numbers can be clicked on. In fact you can see some changes clicking anywhere in the applet area. Click, click, click ... and see what happens.)
What if applet does not run? 
This problem deals with two numbers (ages of boys, or girls, or unicorns  this is quite inessential.) One of the numbers is known, another is not. The key word in the problem is "times". One of the numbers at hand exceeds the second number by a given factor.
The problem at hand belongs to a class of problems described by the equation
(4)  ax = b, 
where x is a variable that denotes the unknown, while a and b are constant (but arbitrary) coefficients.
Equation (4) says that two entities are (or expected to be) equal. One is the number on the right  b. The other (incidentally) a product of two numbers  ax. A quick solution to the equation is obtained following a rule similar to Euclid's
if equals be divided into equals, the results are equal. 
Thus we are prompted to conclude that (ax)/a = b/a, or
(5)  x = b/a, 
that apparently asserts that the unknown is actually equal to b/a. The problem is solved. Or is it?
Do not forget that in (4) coefficients a and b are arbitrary. As far as the equation (4) is concerned, they may be anything. Solving a general equation like (4) is different from solving specific equations like 4x = 12, whose solution is readily obtained as x = 12/4, x = 3. In (4) we are obligated to account for all possible specific cases. Most of the cases are, indeed, handled in the same manner, as in (5). The exception is when a = 0. This is one of characteristic properties of zero that multiplied by another number, any number, it does not change. We may not know x, but if a = 0, then ax is bound to be 0! So unless b is also zero, the equality in (4) is not possible. We arrive at the following cases:

The original problem imposes additional (semantic) constraints. First of all, no one's age can be 0 or negative. Secondly, you would probably be very much surprised to hear a reply "13.5" to a question of yours, "How old are you?" Somewhere in the grade school, where kids of about the same age learn, work, and play together, the difference of a few month loses its significance. From that time on, we count years of our life with integers, discarding the fractional part. This means that in the original word problem it is very natural to assume that all quantities involved are positive integers such that a divides b evenly. (However, this particular fact is not carved in stone. Faced with a similar problem, you may want to check with your teacher.) The same goes for the comon usage of the word times. We never say "1 time as young", let alone "1 times as young."
However, assume the problem reads
A 40 years old father is 7 times older than his son. What is the son's age? 
The formal answer is 40/7 years. Which does not look quite right. For, one would never hear such year count in the context of age determination. Is there a better answer? There might. For example, rounding to the nearest integer, we may suggest that the son's age is 6. This will not mean that
To summarize, above we have looked into three classes of problems. One  that of solving an abstract equation
The names "a" and "b" for the constants in the equation (4) are as arbitrary as they were in the equation
On the one hand, both
Think of the term ax as another unknown.
Word Problems
 Problems of class a + x = b
 Problems of class a · x = b
 From Word Problem to Equation
 Problems of class x / a = b / c
 Problems of class x = a + b
 Problems of class x = a + b (II)
 Problems of class x = a × b
 Solving Two Simultaneous Linear Equations
(There are many more word problems discussed and solved at this site.)
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